diff --git a/src/content/questions/comp2804/2019-fall-final/8/solution.md b/src/content/questions/comp2804/2019-fall-final/8/solution.md
index bd23acab..5595a82b 100644
--- a/src/content/questions/comp2804/2019-fall-final/8/solution.md
+++ b/src/content/questions/comp2804/2019-fall-final/8/solution.md
@@ -2,12 +2,12 @@ I guess we can just think, "total possibilities minus possibilities where both O
 
 <ul>
     <li> Let S be the set of all possibilities <br/> 
-    We choose 1 position out of the 5 positions for the B: 5 <br/> 
-    We choose 2 position out of the 4 remaining positions for the O: $ \binom{4}{2} $ <br/> 
+    We choose 1 position out of the 6 positions for the B: 6 <br/> 
+    We choose 2 position out of the 5 remaining positions for the O: $ \binom{5}{2} $ <br/> 
     We choose 1 position out of the 3 remaining positions for the G: 3 <br/> 
     We choose 1 position out of the 2 remaining positions for the E: 2 <br/> 
     We choose 1 position out of the 1 remaining positions for the R: 1 <br/> 
-    $ |S| = 5 \cdot \binom{4}{2} \cdot 3 \cdot 2 $
+    $ |S| = 6 \cdot \binom{5}{2} \cdot 3 \cdot 2 $
     <li> Let A be the set of all possibilities where both O's are together <br/> 
     Let's treat the two O's as one letter <br/> 
     We have 5 letters: $ G, E, R, B, O $ <br/>