From e1a56890dcc46ef44a8a4b9d38b3f6ccd4d18a71 Mon Sep 17 00:00:00 2001
From: TORUS <42745810+TORUS0818@users.noreply.github.com>
Date: Wed, 25 Jun 2025 23:07:46 +0900
Subject: [PATCH] Create answer.md

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+# Step1
+
+かかった時間：解けず
+
+計算量：
+
+Nをノード数として
+- 時間計算量：O(N)
+- 空間計算量：O(N)
+
+```python
+from lintcode import (
+    TreeNode,
+)
+
+"""
+Definition of TreeNode:
+class TreeNode:
+    def __init__(self, val):
+        self.val = val
+        self.left, self.right = None, None
+"""
+
+class Solution:
+    """
+    @param root: the given tree
+    @param v: the target value
+    @return: the root TreeNode after splitting
+    """
+    def split_b_s_t(self, root: TreeNode, v: int) -> TreeNode:
+        # write your code here
+        def count_nodes(root: TreeNode) -> int:
+            if not root:
+                return 0
+
+            queue = [root]
+            count = 0
+            while queue:
+                next_queue = []
+                for node in queue:
+                    count += 1
+                    if node.left:
+                        next_queue.append(node.left)
+                    if node.right:
+                        next_queue.append(node.right)
+                queue = next_queue
+
+            return count
+
+
+        def split_b_s_t_helper(
+            root: TreeNode,
+            v: int
+            ) -> tuple[TreeNode, TreeNode]:
+            if not root:
+                return None, None
+
+            if root.val <= v:
+                small_root, large_root = split_b_s_t_helper(root.right, v)
+                root.right = small_root
+                return root, large_root
+            else:
+                small_root, large_root = split_b_s_t_helper(root.left, v)
+                root.left = large_root
+                return small_root, root
+
+
+        small_root, large_root = split_b_s_t_helper(root, v)
+
+        small_tree_nodes_count = count_nodes(small_root)
+        large_tree_nodes_count = count_nodes(large_root)
+        if small_tree_nodes_count < large_tree_nodes_count:
+            return large_root
+        if small_tree_nodes_count > large_tree_nodes_count:
+            return small_root
+
+        if small_root.val < large_root.val:
+            return large_root
+        else:
+            return small_root
+```
+思考ログ：
+- leetcodeで有料の問題だったので、lintcodeの該当する問題を解きました
+  - 本家：https://leetcode.com/problems/split-bst/description/  
+  - 若干内容が異なっている模様
+- 一つずつ問題を解決していけばいいものを一気に解決しようとしてよく分からなくなる、という悪い癖が出た
+  - 条件を満たすように木を分ける、ノードの数を数える、ノードの数を比較する、根の値を比較する
+- 木の分割について
+  - ```split_b_s_t_helper```は、ノードを与えると、条件を満たすように2つの木（```small_tree```, ```large_tree```）に分けてそれらのrootを返す関数
+  - 現在のノードの値を確認してv以下なら、そのノードと左の子以降は```small_tree```の部分木になる
+  - ノードの右の子以降は```split_b_s_t_helper```を使って```sub_small_tree```と```sub_large_tree```に分解する
+  - ```small_tree```の右の子に上記の```sub_small_tree```を繋ぐ
+  - ```large_tree```は上記の```sub_large_tree```を採用する
+  - vより大きい場合も同様の考え方
+
+# Step2
+
+講師役目線でのセルフツッコミポイント：
+
+参考にした過去ログなど：
+- https://github.com/ryosuketc/leetcode_arai60/pull/36
+- https://github.com/olsen-blue/Arai60/pull/48
+  - 根から作っていくタイプの解法
+- https://github.com/Ryotaro25/leetcode_first60/pull/50
+  - https://github.com/Ryotaro25/leetcode_first60/pull/50/files#r1912058276
+- https://github.com/goto-untrapped/Arai60/pull/54
+- https://github.com/Yoshiki-Iwasa/Arai60/pull/41
+  - 型について
+    - https://github.com/Yoshiki-Iwasa/Arai60/pull/41/files#r1712673452
+- https://github.com/Mike0121/LeetCode/pull/16
+- https://github.com/shining-ai/leetcode/pull/47
+  - stackに```("go" or "back", root, None)```の形で積んでいく方法
+- https://github.com/hayashi-ay/leetcode/pull/53
+
+```python
+from lintcode import (
+    TreeNode,
+)
+
+"""
+Definition of TreeNode:
+class TreeNode:
+    def __init__(self, val):
+        self.val = val
+        self.left, self.right = None, None
+"""
+
+class Solution:
+    """
+    @param root: the given tree
+    @param v: the target value
+    @return: the root TreeNode after splitting
+    """
+    def split_b_s_t(self, root: TreeNode, v: int) -> TreeNode:
+        # write your code here
+        def count_nodes(root: TreeNode) -> int:
+            if not root:
+                return 0
+
+            queue = [root]
+            count = 0
+            while queue:
+                next_queue = []
+                for node in queue:
+                    count += 1
+                    if node.left:
+                        next_queue.append(node.left)
+                    if node.right:
+                        next_queue.append(node.right)
+                queue = next_queue
+
+            return count
+
+
+        def split_b_s_t_helper(
+            root: TreeNode,
+            v: int
+            ) -> tuple[TreeNode]:
+            if not root:
+                return None, None
+
+            if root.val == v:
+                small_root = root
+                large_root = root.right
+                small_root.right = None
+                return small_root, large_root
+
+            if root.val < v:
+                small_root, large_root = split_b_s_t_helper(root.right, v)
+                root.right = small_root
+                return root, large_root
+            else:
+                small_root, large_root = split_b_s_t_helper(root.left, v)
+                root.left = large_root
+                return small_root, root
+
+
+        small_root, large_root = split_b_s_t_helper(root, v)
+
+        small_tree_nodes_count = count_nodes(small_root)
+        large_tree_nodes_count = count_nodes(large_root)
+        if small_tree_nodes_count < large_tree_nodes_count:
+            return large_root
+        if small_tree_nodes_count > large_tree_nodes_count:
+            return small_root
+
+        if small_root.val < large_root.val:
+            return large_root
+        else:
+            return small_root
+```
+思考ログ：
+- `split_b_s_t_helper`にて、`v`が見つかった時点で打ち切って良い
+
+loop版
+```python
+from lintcode import (
+    TreeNode,
+)
+
+"""
+Definition of TreeNode:
+class TreeNode:
+    def __init__(self, val):
+        self.val = val
+        self.left, self.right = None, None
+"""
+
+class Solution:
+    """
+    @param root: the given tree
+    @param v: the target value
+    @return: the root TreeNode after splitting
+    """
+    def split_b_s_t(self, root: TreeNode, v: int) -> TreeNode:
+        # write your code here
+        def count_nodes(root: TreeNode) -> int:
+            if not root:
+                return 0
+
+            queue = [root]
+            count = 0
+            while queue:
+                next_queue = []
+                for node in queue:
+                    count += 1
+                    if node.left:
+                        next_queue.append(node.left)
+                    if node.right:
+                        next_queue.append(node.right)
+                queue = next_queue
+
+            return count
+
+
+        def split_b_s_t_into_two_subtrees(
+            root: TreeNode,
+            v: int
+        ) -> tuple[TreeNode]:
+            node = root
+            stack = []
+            while node:
+                stack.append(node)
+                if node.val > v:
+                    node = node.left
+                else:
+                    node = node.right
+
+            small_subtree_root = None
+            large_subtree_root = None
+            while stack:
+                node = stack.pop()
+                if node.val > v:
+                    node.left = large_subtree_root
+                    large_subtree_root = node
+                else:
+                    node.right = small_subtree_root
+                    small_subtree_root = node
+
+            return small_subtree_root, large_subtree_root
+
+
+        small_root, large_root = split_b_s_t_into_two_subtrees(root, v)
+
+        small_tree_nodes_count = count_nodes(small_root)
+        large_tree_nodes_count = count_nodes(large_root)
+        if small_tree_nodes_count < large_tree_nodes_count:
+            return large_root
+        if small_tree_nodes_count > large_tree_nodes_count:
+            return small_root
+
+        if small_root.val < large_root.val:
+            return large_root
+        else:
+            return small_root
+```
+- 同じことをやっているのにまだ再帰の方が考えやすい、という感覚がある
+  - 引継ぎの考え方がまだ甘いのとloopをトップダウンで考える癖があるのが原因な気がする
+
+# Step3
+
+かかった時間：11min
+
+```python
+from lintcode import (
+    TreeNode,
+)
+
+"""
+Definition of TreeNode:
+class TreeNode:
+    def __init__(self, val):
+        self.val = val
+        self.left, self.right = None, None
+"""
+
+class Solution:
+    """
+    @param root: the given tree
+    @param v: the target value
+    @return: the root TreeNode after splitting
+    """
+    def split_b_s_t(self, root: TreeNode, v: int) -> TreeNode:
+        # write your code here
+        def count_nodes(root: TreeNode) -> int:
+            if not root:
+                return 0
+
+            stack = [root]
+            count = 0
+            while stack:
+                node = stack.pop()
+                count += 1
+                if node.right:
+                    stack.append(node.right)
+                if node.left:
+                    stack.append(node.left)
+
+            return count
+
+
+        def split_b_s_t(
+            root: TreeNode,
+             v: int
+            ) -> tuple[TreeNode]:
+                if not root:
+                    return None, None
+
+                if root.val == v:
+                    large_root = root.right
+                    small_root = root
+                    small_root.right = None
+                    return small_root, large_root
+
+                if root.val < v:
+                    sub_small_root, sub_large_root = split_b_s_t(
+                        root.right,
+                        v
+                    )
+                    large_root = sub_large_root
+                    small_root = root
+                    small_root.right = sub_small_root
+                    return small_root, large_root
+                else:
+                    sub_small_root, sub_large_root = split_b_s_t(
+                        root.left,
+                        v
+                    )
+                    large_root = root
+                    large_root.left = sub_large_root
+                    small_root = sub_small_root
+                    return small_root, large_root
+
+
+        small_root, large_root = split_b_s_t(root, v)
+        small_tree_size = count_nodes(small_root)
+        large_tree_size = count_nodes(large_root)
+        if small_tree_size == large_tree_size:
+            if small_root.val < large_root.val:
+                return large_root
+            else:
+                return small_root
+
+        if small_tree_size < large_tree_size:
+            return large_root
+        else:
+            return small_root
+```
+思考ログ：
+- 再帰が自然に感じるので再帰で
+- 木の深さ的にも問題なさそう（<<1000）
+
+# Step4
+
+```python
+```
+思考ログ：