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Definition of characteristic strain h_c,n and GW strain amplitude h_0,n #118

@Peggy-Guo

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@Peggy-Guo

Hi Tom,

According to your derivation for characteristic strain - if I am understanding it correctly - it comes from [BarackCutler04]

$$h_{c,n}^2 = \frac{1}{(\pi D_L)^2} \left( \frac{2 G}{c^3} \frac{\dot{E_n}}{\dot{f_n}} \right)$$ eq. (1)

But by referring to these paper I found this equation is cited from [FinnThorne00]

where the definitions of h_c,n and h_0,n are (with c=G=1)

$$h_{c, n}^2 \equiv h_{0, n}^2 \left(\frac{2~f_n^2}{\dot{f}_n} \right)$$ eq.(2)

$$h_{0, n} \equiv \sqrt{\langle h_{+,n}^2 + h_{\times,n}^2\rangle} = \frac{2\sqrt{\dot E_n}}{n \omega_{orb} D_L}$$ eq.(3)

Combine eq (2) and eq (3) we can get eq (1).

However, in your code, h_c is calculated via eq.(1), and h_0 calculated with the new definition without the factor of 2:

$$h_{c, n}^2 = \left(h_{0,n}^2 \frac{f_n^2}{\dot{f}_n} \right)$$

So my question is, is the calculation for h_0 in your code missing a factor of $\sqrt{2}$ since eq (1) is actually a definition comes from eq (2)&(3)? The further question is, if the factor of 2 is already included in the sensitivity curve, could you still use eq.(1) to calculate h_c?

I am confused by the factor of $\sqrt{2}$ difference from my own calculation and legwork calculation for a few days, and I think the question I asked above may be the reason for it. But I wanna double check with you in case I miss anything in your derivation that might also cause this problem!

Thanks!

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