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This repository was archived by the owner on Aug 17, 2019. It is now read-only.
This repository was archived by the owner on Aug 17, 2019. It is now read-only.

luaotfload: reading database #6

@hvoss49

Description

@hvoss49

The following example worked last year:

\documentclass{article}
\setlength{\parindent}{0em}
\usepackage{fontspec}
\usepackage{luacode}
\newfontface\LMML{Latin Modern Mono Light Cond}%% Für die Ausgabe

\begin{luacode}
local teststring = "\\LaTeX~--~Eine Einführung."
local myfonts = luaotfload.aux.read_font_index()
function printFontDemo(fontname)
  local fnA = string.lower(fontname)
  local a = {}
  local b = {}
  for i, v in ipairs(myfonts.mappings) do
    m, n = string.find(string.lower(v.familyname),fnA)
    if m then
      a[v.fontname] = v.familyname
      b[#b + 1] = v.fontname
    end
  end
  table.sort(b)
  for i, v in ipairs(b) do
    tex.print("\\parbox{0.21\\linewidth}{\\LMML\\footnotesize")
    tex.print(-2, a[v])
    tex.print("\\\\ \\scriptsize")
    tex.print(-2, v)
    tex.print("}\\parbox{0.79\\linewidth}{\\raggedright\\setmainfont{" .. v .. "}")
    tex.print(teststring)
    tex.print("}\\\\[2pt]")
  end
end
\end{luacode}
\begin{document}
\directlua{printFontDemo("LatinModern")}
\end{document}

now I get with lualatex 0.95 and up-to-date TL2016

[...]
(/usr/local/texlive/2016/texmf-dist/tex/luatex/ctablestack/ctablestack.sty)))(l
oad luc: /usr/local/texlive/2016/texmf-var/luatex-cache/generic/fonts/otl/lmmon
oltcond10-regular.luc) (./12-04-19.aux)[\directlua]:7: bad argument #1 to 'ipai
rs' (table expected, got nil)
stack traceback:
	[C]: in function 'ipairs'
	[\directlua]:7: in function 'printFontDemo'
	[\directlua]:1: in main chunk.
l.35 \directlua{printFontDemo("LatinModern")}
                                           
? 

I can fix it with the following. Is it a problem with my code or the database which has an empty entry?

  for i, v in ipairs(myfonts.mappings) do
    if v.familyname then
      m, n = string.find(string.lower(v.familyname),fnA)
      if m then
        a[v.fontname] = v.familyname
        b[#b + 1] = v.fontname
      end
    end
  end

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