Ports - Ari (in progress!) #15
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CheezItMan
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May 29, 2019
CheezItMan
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CheezItMan
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I gave some notes on what you have so far.
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| # Time complexity: ? | ||
| # Space complexity: ? | ||
| # Time complexity: O(n), where n is the length of the string |
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Technically s[0, s.length-1] creates a new string of length n-1, so this solution is actually n^2.
| # Time complexity: O(n), where n is the length of the string | ||
| # Space complexity: O(n), because there will be n layers to the call stack. | ||
| def reverse_inplace(s) | ||
| raise NotImplementedError, "Method not implemented" |
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This is not in place.
To do in-place you can create a helper method:
reverse_helper(string, left_index = 0, right_index = string.length -1)
Then each iteration you can swap the characters at left_index and right_index and then call the helper recursively with new values for left_index and right_index. The base case is when left_index == right_index.
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| end | ||
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| # Time complexity: ? |
| # Space complexity: ? | ||
| def bunny(n) | ||
| raise NotImplementedError, "Method not implemented" | ||
| if n % 2 == 0 |
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This should actually be:
return 0 if n == 0
return 2 + bunny(n-1)
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