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CheezItMan
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Sep 19, 2019
CheezItMan
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These methods work, but see my comments on the time complexity. Let me know if you have questions or if I can clarify a bit.
Well done!
| list.each_with_index do |value, index| | ||
| if index > 0 | ||
| if value == list[index - 1] | ||
| list.slice!(index) |
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Slice is going to shift subsequent elements to the left one index. Thus it as a time complexity of O(n). Inside this loop your method as time complexity of O(n2)
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| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) |
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Since you have those two nested loops you actually have a time complexity of O(n2)
| end | ||
| return min_string if commons.length == strings.length | ||
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| until hi <= low |
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Since you never change low, you may not need it. This made me think of binary search and it confused me for a bit.
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