PATCH - Performance can be increased if replaceAll() does not use a r… #14
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…egex by replace replaceAll() with replace(). ReplaceAll() costs some performance overhead by compiling the regex whereas replace() does not incur this performance overhead
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…egex by replacing replaceAll() with replace(). ReplaceAll() costs some performance overhead by compiling the regex whereas replace() does not incur this performance overhead.