fix filter expression with several nodes #4
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A filtering expression like $[?(@.node1.node2)] will not find node2 because the cycle step is 2. If we rewrite the expression for $[?(@.node1.node2.node2)], node2 will be found.
fix filter expression with several nodes
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A filtering expression like
$[?(@.node1.node2)]will not find node2 because the cycle step is 2. If we rewrite the expression for$[?(@.node1.node2.node2)], node2 will be found.