fixed the issues #1
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| # ISSUE 3: This function doesn't handle division by zero properly | ||
| if b == 0: | ||
| return float('inf') # BUG: Should raise an exception instead | ||
| return "Cannot divide by zero" # BUG: Should raise an exception instead |
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correctness: divide returns a string on division by zero instead of raising an exception, violating expected contract and causing inconsistent return types.
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In calculator.py, lines 15-15, the divide function returns a string when dividing by zero instead of raising an exception. This leads to inconsistent return types and violates standard division contract. Change the code to raise a ZeroDivisionError instead of returning a string.
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| return "Cannot divide by zero" # BUG: Should raise an exception instead | |
| if b == 0: | |
| raise ZeroDivisionError("division by zero") |
| # ISSUE 5: This function has recursion issues | ||
| if n < 0: | ||
| return -1 # BUG: Should raise ValueError for negative inputs | ||
| return "Value Error" # BUG: Should raise ValueError for negative inputs |
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correctness: factorial returns a string for negative input instead of raising ValueError, leading to inconsistent return types and silent failures.
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In calculator.py, lines 25-25, the factorial function returns a string for negative input instead of raising a ValueError. This causes inconsistent return types and hides errors. Update the code to raise a ValueError when n < 0.
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| return "Value Error" # BUG: Should raise ValueError for negative inputs | |
| if n < 0: | |
| raise ValueError("factorial() not defined for negative values") |
| print(False) | ||
| else: | ||
| prime = True |
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correctness: is_prime does not return a value for n <= 1, causing undefined behavior and potential runtime errors.
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In calculator.py, lines 33-35, the is_prime function prints False for n <= 1 but does not return a value, leading to undefined behavior. Change the code to return False instead of printing.
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| print(False) | |
| else: | |
| prime = True | |
| if n <= 1: | |
| return False | |
| else: |
| else: | ||
| prime = True | ||
| for i in range(2, int(n**1/2) + 1): | ||
| if n % i == 0: |
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performance: is_prime uses a loop from 2 to int(n**1/2) + 1 but n**1/2 is always 1 for n > 1, causing O(n) time instead of O(sqrt(n)), which is inefficient for large n.
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In calculator.py, line 37, the `is_prime` function uses `int(n**1/2)` which always evaluates to 1 for n > 1, resulting in an inefficient O(n) primality check. Change it to `int(n**0.5)` to achieve O(sqrt(n)) time complexity for large n.
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| if n % i == 0: | |
| for i in range(2, int(n**0.5) + 1): |
1 participant
fixed the issues in calculator.py