Codewars solutions

Even_Odd.py

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+# Create a function (or write a script in Shell) that takes an integer as
+# an argument and returns "Even" for even numbers or "Odd" for odd numbers.
+def even_or_odd(number):
+    if number % 2 == 0:
+        return "Even"
+    else:
+        return "Odd"

First_non_repeating.py

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+# Write a function named first_non_repeating_letter that takes a
+# string input, and returns the first character that is not repeated anywhere in the string.
+#For example, if given the input 'stress',the function should return 't', since the letter
+#t only occurs once in the string, and occurs first in the string.
+#As an added challenge, upper- and lowercase letters are considered the same character, but the function 
+#should return the correct case for the initial letter. For example,the input 'sTreSS' should return 'T'.
+#If a string contains all repeating characters, it should return an empty string ("") or None -- see sample tests.
+def first_non_repeating_letter(string):
+    string_upper = string.upper()
+    upper_string = list(string_upper)
+    string_length = len(upper_string)
+    for i in range(0,string_length):
+        if upper_string.count(upper_string[i]) == 1:  
+            return string[i]
+        else:
+            continue
+    return ""

multiply.py

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+# A function to multiply two numbers
+def multiply(a, b):
+    result=a * b
+    return result

sum_of_digits.py

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+def digital_root(n):
+    if(n < 10):
+        return n
+    n=n%10+digital_root(n//10)
+    return digital_root(n)

vowel_count.py

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+def get_count(input_str):
+    input_str="PYTHON is fun"
+    for char in input_str:
+        if char in "aeiouAEIOU":
+           num_vowels = num_vowels+1
+
+    # your code here
+    return num_vowels